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The probability depends on how many decks are played. Of course the essential ingredients to blackjack are an ace and a One question.


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The probability depends on how many decks are played. Of course the essential ingredients to blackjack are an ace and a One question.


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A blackjack game has a dealer and one or more players. Let's call p the total probability of winning a pass line bet (so p is the number we are trying to calculate). Problems. If you are dealt a point total of 16, what is the probability of busting.


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The probability depends on how many decks are played. Of course the essential ingredients to blackjack are an ace and a One question.


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Probability of obtaining a blackjack from the first two cards is P = 32/ = % in the case of a 1-deck game and P = 64/= % in the case of a


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Objective: Compute the probability of winning in several blackjack situations. Observe the Answers to hand-out questions: 1. answers.


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Thanks for reading? I'm interested in the following situational question - In a standard Double Deck game, What is the probability of being dealt a.


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Your calculation for the first player is correct. Active Oldest Votes. Because the chance of one player getting blackjack is small, the enrichment is small as well, so this is not far off. Sign up to join this community. I don't know if this will get you any closer to a closed form solution, but maybe it helps you think about it. Asked 5 years, 3 months ago. Mathematics Stack Exchange works best with JavaScript enabled.{/INSERTKEYS}{/PARAGRAPH} The outermost branches are short, but the inside of the tree is massive Hopefully this at least helps you contextualize the problem. The best answers are voted up and rise to the top. Blackjack Probability Ask Question. This happens every time. Sign up using Facebook. Nolohice 5 5 silver badges 12 12 bronze badges. Home Questions Tags Users Unanswered. Sign up or log in Sign up using Google. This is not quite correct, as the fact that the first player did not get blackjack enriches the average deck with cards that could make a blackjack for the second player. We're switching to CommonMark. So I deleted the more complicated answer I tried to give earlier. Michael Cotton Michael Cotton 3 3 silver badges 6 6 bronze badges. With a branching factor of five I know , we have two aces, once ace, two whatevers, one 10, two 10s. Related 0. Active 1 year, 7 months ago. I can't help but wonder if there perhaps is a less hideous way of acquiring the same answer though. Question feed. Sign up using Email and Password. Post as a guest Name. Email Required, but never shown. What posts should be escalated to staff using [status-review], and how do Iā€¦. The naive assumption is that the chance of each player getting blackjack is independent of the others. {PARAGRAPH}{INSERTKEYS}Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. Then for the other player we either give them two aces from the 3 that are left, give them one ace from the 3 that are left and 1 of the 32 cards, or give them two non-aces from the 47 non-aces that are left. Viewed 19k times. The probability of both getting blackjack is just the probability of the player getting blackjack and the subsequent probability of the dealer also getting blackjack:. The use of neither indicates that. Featured on Meta. It only takes a minute to sign up. Hot Network Questions. Ross Millikan Ross Millikan k 24 24 gold badges silver badges bronze badges. Suppose that you are playing blackjack against the dealer. MaxWell MaxWell 2 2 bronze badges.